3x^2+4x+12=-10

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Solution for 3x^2+4x+12=-10 equation: 



3x^2+4x+12=-10

We move all terms to the left:

3x^2+4x+12-(-10)=0

We add all the numbers together, and all the variables

3x^2+4x+22=0

a = 3; b = 4; c = +22;
Δ = b2-4ac
Δ = 42-4·3·22
Δ = -248
Delta is less than zero, so there is no solution for the equation

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